3t^2-13=25

Solution for 3t^2-13=25 equation:

3t^2-13=25

We move all terms to the left:

3t^2-13-(25)=0

We add all the numbers together, and all the variables

3t^2-38=0

a = 3; b = 0; c = -38;
Δ = b2-4ac
Δ = 02-4·3·(-38)
Δ = 456
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{456}=\sqrt{4*114}=\sqrt{4}*\sqrt{114}=2\sqrt{114}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{114}}{2*3}=\frac{0-2\sqrt{114}}{6}
=-\frac{2\sqrt{114}}{6}
=-\frac{\sqrt{114}}{3}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{114}}{2*3}=\frac{0+2\sqrt{114}}{6}
=\frac{2\sqrt{114}}{6}
=\frac{\sqrt{114}}{3}
$